2.由调和函数 =(x)^2-(y)^2+2xy 确定的满足-|||-f(1)=1-i 的解析函数 f(z)=u+iv 是(). ()-|||-A (x)=(x)^2-(y)^2+2xy+i((y)^2-(x)^2)-|||-B (x)=(x)^2-(y)^2+2xy+i((y)^2+2xy-(x)^2)-|||-C (x)=(x)^2-(y)^2+2xy+i((y)^2+xy-(x)^2)-|||-D (x)=(x)^2-(y)^2+2xy+i((y)^2-2xy-(x)^2)